Math Problem Statement

Find the center-radius form of the equation of the circle with center (4,8) and radius 8.

Solution

The question asks for the center-radius form of the equation of a circle with a center at (4,8)(4, 8) and a radius of 8.

The general formula for the equation of a circle is:

(xh)2+(yk)2=r2(x - h)^2 + (y - k)^2 = r^2

where:

  • (h,k)(h, k) is the center of the circle, and
  • rr is the radius.

Given:

  • Center: (4,8)(4, 8), so h=4h = 4 and k=8k = 8,
  • Radius: r=8r = 8, so r2=64r^2 = 64.

Substitute these values into the formula:

(x4)2+(y8)2=64(x - 4)^2 + (y - 8)^2 = 64

This matches option A in the multiple-choice list.

So, the correct answer is A: (x4)2+(y8)2=64(x - 4)^2 + (y - 8)^2 = 64.

Would you like more details or have any questions about this? Here are five related questions to deepen your understanding:

  1. What would the equation look like if the radius were doubled?
  2. How would the equation change if the center were moved to (4,8)(-4, -8)?
  3. How do you find the equation of a circle given a point on its circumference and the center?
  4. What is the geometric significance of the terms (xh)2(x - h)^2 and (yk)2(y - k)^2?
  5. Can you find the equation of a circle passing through the origin with a center at (4,8)(4, 8)?

Tip: Remember, the sign inside the parentheses in the equation of a circle is always opposite to the coordinates of the center!

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Math Problem Analysis

Mathematical Concepts

Geometry
Equations of Circles

Formulas

(x - h)^2 + (y - k)^2 = r^2

Theorems

Equation of a Circle

Suitable Grade Level

Grades 9-12