Math Problem Statement

Write the standard form of the equation of the circle whose radius is r and whose center is (h, k). r = 4; (h, k) = (-8, 0)

Solution

To find the standard form of the equation of a circle, we use the formula:

(xh)2+(yk)2=r2(x - h)^2 + (y - k)^2 = r^2

Here:

  • h=8h = -8
  • k=0k = 0
  • r=4r = 4

Substitute these values into the formula:

(x(8))2+(y0)2=42(x - (-8))^2 + (y - 0)^2 = 4^2

This simplifies to:

(x+8)2+y2=16(x + 8)^2 + y^2 = 16

So, the correct answer is the fourth option:

(x+8)2+y2=16(x + 8)^2 + y^2 = 16

Would you like more details or have any questions about this solution?

Here are 5 related questions to deepen your understanding:

  1. How would the equation change if the radius were doubled?
  2. What is the general formula for the equation of a circle?
  3. How does the equation of a circle change if the center is at the origin?
  4. Can the center of a circle have negative coordinates, and how does that affect the equation?
  5. How do you find the radius of a circle if the equation is already given in standard form?

Tip: When writing the equation of a circle, remember that (h,k)(h, k) represents the coordinates of the circle's center, and the sign in the equation is always the opposite of the signs of hh and kk in the coordinate form.

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Math Problem Analysis

Mathematical Concepts

Geometry
Circles
Equation of a Circle

Formulas

(x - h)^2 + (y - k)^2 = r^2

Theorems

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Suitable Grade Level

Grades 9-11