Math Problem Statement

Find the equation of a circle centered at (1, -8) with radius √10.

Solution

To solve this problem, we need to use the standard form of the equation of a circle, which is given by:

(xh)2+(yk)2=r2(x - h)^2 + (y - k)^2 = r^2

Here:

  • (h,k)(h, k) represents the coordinates of the center of the circle.
  • rr represents the radius of the circle.

Given:

  • The center of the circle is (1,8)(1, -8), so h=1h = 1 and k=8k = -8.
  • The radius rr is 10\sqrt{10}.

Now, let's substitute these values into the equation:

(x1)2+(y(8))2=(10)2(x - 1)^2 + \left(y - (-8)\right)^2 = (\sqrt{10})^2

Simplifying this equation:

(x1)2+(y+8)2=10(x - 1)^2 + (y + 8)^2 = 10

So, the correct equation of the circle is:

(x1)2+(y+8)2=10(x - 1)^2 + (y + 8)^2 = 10

This corresponds to the second option in the image.

Would you like more details or have any questions?


Here are five related questions to expand on this concept:

  1. How would the equation change if the circle's center was at the origin?
  2. What is the significance of the coefficients of xx and yy in the circle's equation?
  3. How would the equation of the circle change if the radius was doubled?
  4. Can you derive the equation of a circle given a different center and radius?
  5. How would you determine the center and radius of a circle from a given equation in general form?

Tip: Always ensure that the terms are correctly expanded and simplified when dealing with the equation of a circle to avoid errors in identifying the correct form.

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Math Problem Analysis

Mathematical Concepts

Geometry
Equations of Circles

Formulas

(x - h)^2 + (y - k)^2 = r^2

Theorems

Equation of a Circle

Suitable Grade Level

Grades 9-11