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To solve the problem:

Cyrus runs at a constant speed of **200 meters per minute**. The question asks what points he would plot on the graph for times of **8 minutes** and **12 minutes**. The **x-axis** represents time (in minutes), and the **y-axis** represents distance (in meters).

1. **For 8 minutes:**
   - Distance = Speed × Time
   - Distance = \( 200 \, \text{meters/minute} \times 8 \, \text{minutes} = 1600 \, \text{meters} \)
   - So, the point for 8 minutes is \( (8, 1600) \).

2. **For 12 minutes:**
   - Distance = Speed × Time
   - Distance = \( 200 \, \text{meters/minute} \times 12 \, \text{minutes} = 2400 \, \text{meters} \)
   - So, the point for 12 minutes is \( (12, 2400) \).

### Conclusion:
The points to be plotted are:
- \( (8, 1600) \) for 8 minutes.
- \( (12, 2400) \) for 12 minutes.

Would you like further details or explanations? Here are some related questions:

1. What would the point be for 5 minutes of running?
2. How far would Cyrus run in 15 minutes at this speed?
3. If Cyrus increased his speed to 250 meters per minute, how would the points change?
4. How do you calculate the slope of the graph based on these points?
5. What would the graph look like for someone running at half of Cyrus's speed?

**Tip:** The graph of distance versus time for a constant speed is a straight line, and the slope of this line represents the speed.

Cyrus runs on a track at a constant speed of 200 meters per minute. Later, he makes a graph of his run to show his coach. He puts time on the x-axis and distance on the y-axis. What points does he plot to show how far he runs in 8 minutes and 12 minutes?

Learn how to calculate and plot the points for a runner moving at a constant speed of 200 meters per minute. Discover the points on a graph for 8 and 12 minutes and understand how distance relates to time in linear motion.

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