Math Problem Statement

For the points P and​ Q, find the distance​ d(P,Q). ​P(55​,negative 2−2​), ​Q(negative 6−6​,44​)

Solution

To find the distance between two points P(x1,y1)P(x_1, y_1) and Q(x2,y2)Q(x_2, y_2), we use the distance formula:

d(P,Q)=(x2x1)2+(y2y1)2d(P,Q) = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Given points P(55,2)P(55, -2) and Q(6,44)Q(-6, 44), the coordinates are:

  • x1=55x_1 = 55, y1=2y_1 = -2
  • x2=6x_2 = -6, y2=44y_2 = 44

Now apply these to the formula:

d(P,Q)=((655)2)+((44(2))2)d(P, Q) = \sqrt{((-6 - 55)^2) + ((44 - (-2))^2)} =(61)2+(44+2)2= \sqrt{(-61)^2 + (44 + 2)^2} =3721+462= \sqrt{3721 + 46^2} =3721+2116= \sqrt{3721 + 2116} =5837= \sqrt{5837}

The approximate distance is:

d(P,Q)76.39d(P, Q) \approx 76.39

The distance between points PP and QQ is approximately 76.39 units.

Would you like further details or have any questions?


Here are 5 related questions:

  1. How do you find the midpoint between two points?
  2. How would the distance formula change in three-dimensional space?
  3. Can you find the slope between points PP and QQ?
  4. What are real-world applications of the distance formula?
  5. How does the distance formula relate to the Pythagorean theorem?

Tip: Always double-check signs when substituting coordinates into the distance formula to avoid common errors.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Geometry
Coordinate Geometry
Distance Between Two Points

Formulas

Distance formula: d(P, Q) = √((x2 - x1)² + (y2 - y1)²)

Theorems

Pythagorean Theorem

Suitable Grade Level

Grades 8-10