Math Problem Statement

The coordinates of points P and Q are (4,3) and (2,-1) respectively. Find the shortest distance between P and Q.

Solution

The image shows a problem asking for the shortest distance between two points P(4,3)P(4,3) and Q(2,1)Q(2,-1). The distance formula between two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is:

d=(x2x1)2+(y2y1)2d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Substituting the coordinates of P(4,3)P(4,3) and Q(2,1)Q(2,-1):

d=(24)2+(13)2d = \sqrt{(2 - 4)^2 + (-1 - 3)^2} d=(2)2+(4)2d = \sqrt{(-2)^2 + (-4)^2} d=4+16d = \sqrt{4 + 16} d=20=25d = \sqrt{20} = 2\sqrt{5}

So, the shortest distance between points PP and QQ is 252\sqrt{5}.

Would you like further details or have any questions?

Here are 5 related questions to expand on this:

  1. How do you generalize the distance formula to 3D coordinates?
  2. What is the midpoint between points P(4,3)P(4,3) and Q(2,1)Q(2,-1)?
  3. How do you calculate the slope of the line passing through points PP and QQ?
  4. If point RR lies on the line joining PP and QQ, what would be the ratio of distances if RR divides PQPQ internally?
  5. How does the Pythagorean theorem relate to the distance formula in a coordinate plane?

Tip: When using the distance formula, always double-check the signs of the differences between coordinates to avoid mistakes.

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Math Problem Analysis

Mathematical Concepts

Coordinate Geometry
Distance Formula
Pythagorean Theorem

Formulas

Distance formula: d = sqrt((x2 - x1)^2 + (y2 - y1)^2)

Theorems

Pythagorean Theorem

Suitable Grade Level

Grades 9-10