Math Problem Statement

The line segment connects P(-4, 1) and Q(4, 5). Determine the length PQ. Give your answer correct to 1 decimal place.

Solution

We need to calculate the length of the line segment PQPQ using the distance formula:

d=(x2x1)2+(y2y1)2d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Here, the coordinates of PP are (4,1)(-4, 1) and the coordinates of QQ are (4,5)(4, 5). Substituting into the formula:

d=(4(4))2+(51)2d = \sqrt{(4 - (-4))^2 + (5 - 1)^2}

d=(4+4)2+(51)2d = \sqrt{(4 + 4)^2 + (5 - 1)^2}

d=82+42d = \sqrt{8^2 + 4^2}

d=64+16d = \sqrt{64 + 16}

d=80d = \sqrt{80}

d=8.9(rounded to one decimal place).d = 8.9 \, \text{(rounded to one decimal place)}.

Thus, the length of PQPQ is 8.9 units.

Would you like further details or explanations?


Related Questions

  1. How is the distance formula derived from the Pythagorean theorem?
  2. How can you verify the result using another method?
  3. What is the midpoint of the segment PQPQ?
  4. How can the slope of the line segment PQPQ be calculated?
  5. What are some applications of the distance formula in real-life problems?

Tip

Always double-check calculations by substituting values back into the equation to confirm accuracy.

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Math Problem Analysis

Mathematical Concepts

Analytic Geometry
Distance between Points

Formulas

Distance Formula: d = sqrt((x2 - x1)^2 + (y2 - y1)^2)

Theorems

Pythagorean Theorem

Suitable Grade Level

Grades 7-10