Math Problem Statement
Solution
We are tasked with differentiating two functions:
A)
B)
I will solve each part step-by-step:
Part A: Differentiating
We use the logarithmic differentiation technique because the power includes a variable expression.
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Take the natural logarithm of both sides:
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Differentiate both sides with respect to , applying the product rule on the right-hand side:
Using the product rule: [ \frac{d}{dx} \left[ (1 + x^2) \ln (\sin x) \right] = \frac{d}{dx} (1 + x^2) \cdot \ln (\sin x) + (1 + x^2) \cdot \frac{d}{dx} [\ln (\sin x)] ]
So:
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Multiply through by to isolate :
Part B: Differentiating
Here we use the chain rule and the logarithmic property .
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Split the logarithm:
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Differentiate both terms separately:
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For , use the chain rule:
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For :
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Combine the results:
Final Answers:
- A)
- B)
Let me know if you'd like a detailed verification for any step or further clarification!
Related Questions:
- How do you differentiate functions with variable exponents using logarithmic differentiation?
- What is the product rule, and how does it apply to differentiation?
- Can you explain how to differentiate logarithmic functions like ?
- How does the chain rule work in composite functions such as ( \ln (\sin x
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Math Problem Analysis
Mathematical Concepts
Logarithmic Differentiation
Chain Rule
Product Rule
Derivative of Logarithmic Functions
Formulas
d/dx [u^v] = u^v [v'ln(u) + v(u'/u)] (Logarithmic Differentiation)
d/dx [ln(u)] = u'/u
d/dx [uv] = u'v + uv' (Product Rule)
Theorems
Chain Rule
Logarithmic Properties: ln(a/b) = ln(a) - ln(b)
Suitable Grade Level
Undergraduate Calculus or Advanced High School (AP Calculus)
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