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The question asks to determine the width of each class based on the table provided.

The table presents class intervals for "Years employed at Alpha Corporation" (years of service) and their frequencies (number of employees):

| Class Limits (years of service) | Frequency (No. of employees) |
| --- | --- |
| 1–5  | 5 |
| 6–10 | 20 |
| 11–15 | 25 |
| 16–20 | 10 |
| 21–25 | 5 |
| 26–30 | 3 |

The "class width" is the difference between the upper and lower boundaries of any class. For example, for the first class (1–5 years), the width is:

\[
\text{Class width} = 5 - 1 + 1 = 5
\]

The "+1" is added to account for inclusive class limits. We can check the same for all other intervals, and the width will consistently be 5.

Thus, the correct answer is:

**A. 5**

Would you like more details or have any other questions? Here are 5 related questions you might find helpful:

1. What is the formula for class width in frequency distribution tables?
2. How would you interpret the meaning of frequency in a dataset?
3. What are some different ways to display frequency distribution?
4. How can class width affect the interpretation of a histogram?
5. How would you calculate the midpoint of each class?

**Tip:** In frequency distributions, consistency in class width is important for accurate data representation in histograms and bar charts!

Using the employment information in the table on Alpha Corporation, determine the width of each class.

Learn how to determine the class width for each interval in a frequency distribution table, using an example of employees' years of service at Alpha Corporation. This problem covers key concepts in statistics and frequency distribution, suitable for Grades 7-9 students.

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