The image shows a frequency distribution table with classes and corresponding frequencies. To solve this problem, I need to calculate $K$, which likely refers to the class width or another statistical measure.

Here's the breakdown of the steps to solve it:

1. Identify Class Width ($K$):

   • The class intervals are given as:
     • $0 - 9$
     • $10 - 14$
     • $15 - 19$
     • $20 - 24$
     • $25$ and above (cumulative)
   • If $K$ represents the class width, calculate it using the first two intervals: $K = 10 - 5 = 5$

2. Determine the value of $K$:

   • $K$ could also represent the number of classes, cumulative frequency, or other measure.
   • Let's calculate the cumulative frequency from the given dataThe image shows a frequency distribution table with classes and corresponding frequencies. To solve this problem, I need to calculate $K$, which likely refers to the class width or another statistical measure.

Here's the breakdown of the steps to solve it:

1. Identify Class Width ($K$):

   • The class intervals are given as:
     • $0 - 9$
     • $10 - 14$
     • $15 - 19$
     • $20 - 24$
     • $25$ and above (cumulative)
   • If $K$ represents the class width, calculate it using the first two intervals: $K = 10 - 5 = 5$

2. Determine the value of $K$:

   • $K$ could also represent the number of classes, cumulative frequency, or other measure.
   • Let's calculate the cumulative frequency from the given
     • Class $0 - 9$ has a frequency of 5.
     • Class $10 - 14$ has a frequency of $K$ (Unknown).
     • Class $15 - 19$ has a frequency of 8.
     • Class $20 - 24$ has a frequency of 5.
     • The cumulative frequency for $25$ and above is 48.
   • The cumulative frequencies can be calculated as: $\text{Cumulative frequency for } 0 - 9 = 5$ $\text{Cumulative frequency for } 10 - 14 = 5 + K$ $\text{Cumulative frequency for } 15 - 19 = 5 + K + 8$ $\text{Cumulative frequency for } 20 - 24 = 5 + K + 8 + 5$
   • The total cumulative frequency is given as 48. Therefore: $5 + K + 8 + 5 = 48$
   • Solve for $K$: $K + 18 = 48$