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The image shows a frequency distribution table with classes and corresponding frequencies. To solve this problem, I need to calculate \( K \), which likely refers to the class width or another statistical measure.

Here's the breakdown of the steps to solve it:

1. **Identify Class Width (\( K \)):**
   - The class intervals are given as:
     - \(0 - 9\)
     - \(10 - 14\)
     - \(15 - 19\)
     - \(20 - 24\)
     - \(25\) and above (cumulative)
   - If \( K \) represents the class width, calculate it using the first two intervals:
     \[
     K = 10 - 5 = 5
     \]

2. **Determine the value of \( K \):**
   - \( K \) could also represent the number of classes, cumulative frequency, or other measure.
   - Let's calculate the cumulative frequency from the given dataThe image shows a frequency distribution table with classes and corresponding frequencies. To solve this problem, I need to calculate \( K \), which likely refers to the class width or another statistical measure.

Here's the breakdown of the steps to solve it:

1. **Identify Class Width (\( K \)):**
   - The class intervals are given as:
     - \(0 - 9\)
     - \(10 - 14\)
     - \(15 - 19\)
     - \(20 - 24\)
     - \(25\) and above (cumulative)
   - If \( K \) represents the class width, calculate it using the first two intervals:
     \[
     K = 10 - 5 = 5
     \]

2. **Determine the value of \( K \):**
   - \( K \) could also represent the number of classes, cumulative frequency, or other measure.
   - Let's calculate the cumulative frequency from the given 
     - Class \(0 - 9\) has a frequency of 5.
     - Class \(10 - 14\) has a frequency of \( K \) (Unknown).
     - Class \(15 - 19\) has a frequency of 8.
     - Class \(20 - 24\) has a frequency of 5.
     - The cumulative frequency for \(25\) and above is 48.
   - The cumulative frequencies can be calculated as:
     \[
     \text{Cumulative frequency for } 0 - 9 = 5
     \]
     \[
     \text{Cumulative frequency for } 10 - 14 = 5 + K
     \]
     \[
     \text{Cumulative frequency for } 15 - 19 = 5 + K + 8
     \]
     \[
     \text{Cumulative frequency for } 20 - 24 = 5 + K + 8 + 5
     \]
   - The total cumulative frequency is given as 48. Therefore:
     \[
     5 + K + 8 + 5 = 48
     \]
   - Solve for \( K \):
     \[
     K + 18 = 48
     \]
    

Learn how to solve a frequency distribution table problem involving class width calculation. This problem covers statistical concepts such as frequency distribution and cumulative frequency. Suitable for students in Grades 10-12.

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