Math Problem Statement

Consider the following frequency table representing the distribution of the price of a newspaper (in dollars).

Price of a Newspaper (in Dollars)ClassFrequency

0.20–0.290.20–0.29

88

0.30–0.390.30–0.39

88

0.40–0.490.40–0.49

1414

0.50–0.590.50–0.59

1111

0.60–0.690.60–0.69

77

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Determine the class width of each class.

Solution

To correctly determine the class width for each class in the frequency table, we use the following formula:

Class Width=Lower Class Limit of Next ClassLower Class Limit of Current Class\text{Class Width} = \text{Lower Class Limit of Next Class} - \text{Lower Class Limit of Current Class}

Let’s calculate the class width for the given classes.

1st Class: 0.200.290.20 - 0.29

The lower class limit of the next class is 0.300.30. Class Width=0.300.20=0.10\text{Class Width} = 0.30 - 0.20 = 0.10

2nd Class: 0.300.390.30 - 0.39

The lower class limit of the next class is 0.400.40. Class Width=0.400.30=0.10\text{Class Width} = 0.40 - 0.30 = 0.10

3rd Class: 0.400.490.40 - 0.49

The lower class limit of the next class is 0.500.50. Class Width=0.500.40=0.10\text{Class Width} = 0.50 - 0.40 = 0.10

4th Class: 0.500.590.50 - 0.59

The lower class limit of the next class is 0.600.60. Class Width=0.600.50=0.10\text{Class Width} = 0.60 - 0.50 = 0.10

5th Class: 0.600.690.60 - 0.69

There is no next class, but we

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Math Problem Analysis

Mathematical Concepts

Statistics
Class Width
Frequency Distribution

Formulas

Class Width = Lower Class Limit of Next Class - Lower Class Limit of Current Class

Theorems

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Suitable Grade Level

Grades 9-12