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We are given the function:

\[
y = (2x + 3)(5x^2 - 4x)
\]

We are tasked with finding the first and second derivatives of this function. 

### Step 1: Expand the function

First, let's expand the product:

\[
y = (2x + 3)(5x^2 - 4x)
\]

Using distribution:

\[
y = (2x)(5x^2 - 4x) + (3)(5x^2 - 4x)
\]

\[
y = 2x(5x^2) - 2x(4x) + 3(5x^2) - 3(4x)
\]

\[
y = 10x^3 - 8x^2 + 15x^2 - 12x
\]

Combine like terms:

\[
y = 10x^3 + 7x^2 - 12x
\]

### Step 2: First derivative (dy/dx)

Now, differentiate term by term:

\[
\frac{dy}{dx} = \frac{d}{dx}(10x^3) + \frac{d}{dx}(7x^2) + \frac{d}{dx}(-12x)
\]

\[
\frac{dy}{dx} = 30x^2 + 14x - 12
\]

### Step 3: Second derivative (d²y/dx²)

Now, differentiate the first derivative:

\[
\frac{d^2y}{dx^2} = \frac{d}{dx}(30x^2 + 14x - 12)
\]

\[
\frac{d^2y}{dx^2} = 60x + 14
\]

### Summary

- First derivative: \(\frac{dy}{dx} = 30x^2 + 14x - 12\)
- Second derivative: \(\frac{d^2y}{dx^2} = 60x + 14\)

Would you like further clarification or a breakdown of any of the steps?

Here are some related questions to explore further:
1. How do we apply the product rule for derivatives?
2. What is the importance of the second derivative in curve analysis?
3. How do we interpret the first derivative in terms of function behavior?
4. Can we derive higher-order derivatives for this function?
5. What is the geometric significance of the second derivative?

**Tip:** Always simplify the function first before differentiating, as it makes the process easier and less error-prone.

Find the first and second derivatives of y = (2x + 3)(5x^2 - 4x).

Learn how to find the first and second derivatives of the function y = (2x + 3)(5x^2 - 4x) using product and power rules. This problem covers key calculus concepts, including polynomial differentiation. Suitable for students in Grades 11-12.

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