To find the derivative of the function f(x)=(x2−4x+2)(5x3−x2+4), we can apply the product rule. The product rule states that if f(x)=g(x)⋅h(x), then:
f′(x)=g′(x)⋅h(x)+g(x)⋅h′(x)
Here, we have:
- g(x)=x2−4x+2
- h(x)=5x3−x2+4
Step 1: Differentiate g(x) and h(x)
- Differentiate g(x)=x2−4x+2:
g′(x)=2x−4
- Differentiate h(x)=5x3−x2+4:
h′(x)=15x2−2x
Step 2: Apply the product rule
Now, using the product rule:
f′(x)=g′(x)⋅h(x)+g(x)⋅h′(x)
Substitute the values of g(x), g′(x), h(x), and h′(x):
f′(x)=(2x−4)(5x3−x2+4)+(x2−4x+2)(15x2−2x)
Step 3: Simplify the expression
Now, expand both terms:
- Expand (2x−4)(5x3−x2+4):
(2x−4)(5x3−x2+4)=2x(5x3−x2+4)−4(5x3−x2+4)
=10x4−2x3+8x−20x3+4x2−16
=10x4−22x3+4x2+8x−16
- Expand (x2−4x+2)(15x2−2x):
(x2−4x+2)(15x2−2x)=x2(15x2−2x)−4x(15x2−2x)+2(15x2−2x)
=15x4−2x3−60x3+8x2+30x2−4x
=15x4−62x3+38x2−4x
Step 4: Combine the results
Now combine the expanded terms from both parts:
f′(x)=(10x4−22x3+4x2+8x−16)+(15x4−62x3+38x2−4x)
f′(x)=(10x4+15x4)+(−22x3−62x3)+(4x2+38x2)+(8x−4x)−16
f′(x)=25x4−84x3+42x2+4x−16
Final Answer:
The derivative of f(x) is:
f′(x)=25x4−84x3+42x2+4x−16
Would you like a more detailed explanation on any part, or do you have other questions?
Here are some related questions for further practice:
- How would you apply the product rule to functions with more than two factors?
- What is the chain rule, and how does it differ from the product rule?
- How do you simplify a complex polynomial expression after differentiation?
- What is the derivative of a quotient of two functions?
- How can you find higher-order derivatives of polynomial functions?
Tip: When applying the product rule, always remember to differentiate each function separately and then apply the rule step by step!