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The image presents a number partitioning problem where you're tasked with finding the missing digit in the number \( 73.1\_6 \) (marked as box **A**) and determining the value for box **B** in the equation below:

\[
73.1\_6 = 70 + 3 + 0.1 + 0.02 + \text{(B)}
\]

### Step-by-Step Solution:

1. The number given is \( 73.1\_6 \), which must match the sum of the right-hand side.

2. The sum of the known parts is:

\[
70 + 3 + 0.1 + 0.02 = 73.12
\]

3. We need to complete the equation \( 73.1\_6 \) with the missing digit in **A** and find the missing number in **B**.

4. Let's assume the missing digit in **A** is \( x \). So the number is \( 73.1x6 \).

5. \( 73.1x6 = 73.12 + B \).

   Since we're working with a number \( 73.1x6 \), we can infer that the missing digit **A** is 4 because the number would then be \( 73.146 \), which is very close to the sum \( 73.12 + 0.006 \).

6. Therefore:
   - The missing digit in box **A** is **4**.
   - The number in box **B** is **0.006**.

### Final Answer:

- **A = 4**
- **B = 0.006**

Let me know if you need further clarification or additional details.

Here are 5 related questions:
1. How do you break down a decimal number into parts?
2. What is the process to identify a missing digit in a decimal?
3. How can decimal places be represented in partition form?
4. Why does \( 0.006 \) complete the sum in this case?
5. How can we use place values to reconstruct numbers like \( 73.146 \)?

**Tip:** When working with decimals, understanding the place value system (tenths, hundredths, thousandths) is crucial for correctly identifying and placing digits.

Fill in the missing digit and the missing number to complete the partition. Write down the numbers that should appear in boxes A and B.

This problem challenges students to complete a partition by filling in a missing digit and number in a decimal format. Learn how to use place values to solve 73.1_6 = 70 + 3 + 0.1 + 0.02 + __, ideal for Grade 4-5 students.

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