Math Problem Statement
so why is series 1/(n^2+1) divergent
Solution
To determine whether the series converges or diverges, we need to analyze the behavior of its terms and possibly compare it to a known convergent or divergent series.
One useful comparison is with the series , which is a well-known convergent series (the p-series with ).
Let's compare the terms of our series with :
While is less than , this comparison alone does not help us determine the divergence or convergence because it does not satisfy the conditions needed for a comparison test to prove divergence. Instead, we should directly consider the behavior of the series itself.
We can use the Limit Comparison Test to compare with :
Since the limit is a finite, non-zero constant (in this case, 1), the Limit Comparison Test tells us that converges if and only if converges. Because is a convergent p-series with , the series also converges.
Therefore, the series does not diverge; it converges.
Would you like further details or have any questions about this explanation?
Here are some more questions you might be interested in:
- Why does the series diverge?
- How do you determine if a series converges or diverges using the Ratio Test?
- What is the difference between absolute and conditional convergence?
- Can you explain the Alternating Series Test?
- How do you apply the Integral Test to determine the convergence of a series?
Tip: The Limit Comparison Test is a powerful tool for determining the convergence or divergence of a series by comparing it with another series whose behavior is already known.
Ask a new question for Free
By Image
Drop file here or Click Here to upload
Math Problem Analysis
Mathematical Concepts
Series convergence
Limit comparison test
P-series
Formulas
Limit comparison test: \( \lim_{{n \to \infty}} \frac{a_n}{b_n} \)
Theorems
P-series convergence: \( \sum_{n=1}^{\infty} \frac{1}{n^p} \) converges if \( p > 1 \)
Suitable Grade Level
Advanced
Related Recommendation
Determine Convergence of Series Using the Direct Comparison Test
Determine Convergence or Divergence of the Series \( \sum_{n=1}^{\infty} \frac{1}{n^2 + 1} \)
Understanding Convergence of Series: Simplifying \(\frac{n+1}{n^2}\)
Why Does \( \sum_{n=1}^{\infty} \frac{n+1}{n^2} \) Converge? Detailed Explanation
Convergence of the Series 3/(n^2 + 3) Using the Comparison Test