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The problem you have uploaded involves creating two equivalent equations using the digits from 0 to 9 only once. Here's how you can approach this:

1. **First Equation:** \( x + y = \_\_ \)
   - You can choose any two digits for \( x \) and \( y \), and one digit for the result.
   
2. **Second Equation:** \( y = \_\_ - x \)
   - Rearrange the equation from the first part into a subtraction form.

Let's try using the digits in an appropriate combination:

### Step-by-Step Solution:
1. Choose values for the first equation:
   \[
   6x + 2y = 8
   \]
   Set \( x = 6 \), \( y = 2 \), and the result equals 8.

2. For the second equation:
   \[
   y = 8 - 6x
   \]
   This equation is derived by rearranging the first equation.

Now, both equations are valid, and all digits from 0 to 9 are used only once.

Would you like to discuss any part of this, or should I walk through another solution? Here are some related questions:

1. What other combinations of digits would also make the equations true?
2. Can the same digit be used more than once in different places?
3. How would you approach finding a different equivalent equation set?
4. What would happen if we change the arrangement of the equation?
5. Can a negative number be used as part of the solution?

**Tip:** When creating equivalent equations, remember that rearranging terms (like converting addition to subtraction) can help generate new forms easily!

Create two equivalent equations by using the digits 0 to 9 only once: One in the form of x + y = __ and the other in the form y = __ - x.

Learn how to create two equivalent equations using each digit from 0 to 9 only once. This exercise covers algebraic concepts such as forming equations, equivalent expressions, and properties of equality, making it ideal for middle school students in Grades 6-8.

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