Math Problem Statement

A 8-centimeter rod is attached at one end to a point A rotating counterclockwise on a wheel of radius 4 cm. The other end B is free to move back and forth along a horizontal bar that goes through the center of the wheel. At time t=0 the rod is situated as in the diagram at the left below. The wheel rotates counterclockwise at 2.0 revolutions per second. When t=1/12 sec, point A has coordinates (2, 2√3) and point B has coordinates (10, 0).

Solution

To find the coordinates of Point BB at t=112t = \frac{1}{12} seconds, we need to analyze the rotation of Point AA around the origin.

Given Information:

  1. The wheel has a radius of 44 cm.
  2. Point AA is attached to a rod of length 88 cm, with BB being free to slide horizontally.
  3. The wheel rotates at 2.02.0 revolutions per second counterclockwise.
  4. At t=0t = 0, the rod is horizontal, with AA located at (4,0)(4, 0).

Step-by-Step Solution:

  1. Calculate the angle at t=112t = \frac{1}{12} sec:

    • The wheel completes 2.02.0 revolutions per second, meaning each revolution takes 12\frac{1}{2} seconds.
    • In 112\frac{1}{12} seconds, the angle rotated is: Angle=22π112=π3 radians\text{Angle} = 2 \cdot 2\pi \cdot \frac{1}{12} = \frac{\pi}{3} \text{ radians}
  2. Determine coordinates of Point AA:

    • Since the radius of the wheel is 44 cm, and the wheel rotates counterclockwise, the new position of AA forms an angle of π3\frac{\pi}{3} with the positive xx-axis.
    • Therefore, the coordinates of AA at t=112t = \frac{1}{12} sec are: x=4cos(π3)=412=2x = 4 \cos\left(\frac{\pi}{3}\right) = 4 \cdot \frac{1}{2} = 2 y=4sin(π3)=432=23y = 4 \sin\left(\frac{\pi}{3}\right) = 4 \cdot \frac{\sqrt{3}}{2} = 2\sqrt{3}
    • So, AA is at (2,23)(2, 2\sqrt{3}).
  3. Determine coordinates of Point BB:

    • Point BB lies horizontally to the right of AA, at a distance of 88 cm.
    • Since AA is at (2,23)(2, 2\sqrt{3}), BB's xx-coordinate will be 2+8=102 + 8 = 10, and its yy-coordinate will be the same as AA's yy-coordinate, which is 00.

Final Answer:

  • Point AA coordinates: (2,23)\left(2, 2\sqrt{3}\right)
  • Point BB coordinates: (10,0)(10, 0)

Would you like further details on this solution or have any questions?

Related Questions

  1. How would the coordinates change if the wheel rotated clockwise?
  2. What would happen if the rod length was different, say 1010 cm?
  3. How would the coordinates of BB vary if BB could slide vertically instead of horizontally?
  4. What is the angular velocity of Point AA in radians per second?
  5. How does the period of rotation affect the positions of AA and BB?

Tip

Remember that angular displacement in radians can be found by multiplying the angular velocity by time.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Circular motion
Coordinate geometry

Formulas

x = r * cos(θ)
y = r * sin(θ)
θ = ω * t, where ω is angular velocity

Theorems

Trigonometric functions for circular motion

Suitable Grade Level

Grades 10-12