Math Problem Statement

A 10-centimeter rod is attached at one end to a point A rotating counterclockwise on a wheel of radius 5 cm. The other end B is free to move back and forth along a horizontal bar that goes through the center of the wheel. At time t=1/18 sec, the rod is situated as in the diagram. The wheel rotates counterclockwise at 3.0 revolutions per second.

Solution

Let's analyze each part of the question you answered:

  1. Part (a) - The coordinates for point AA and BB are correct:

    • AA at (2.5,4.33)(2.5, 4.33)
    • BB at (12.5,0)(12.5, 0)
  2. Part (b) - The angular velocity, ω=6π\omega = 6\pi radians per second, is also correct.

  3. Part (c) - The expressions for the xx- and yy-coordinates of point AA as functions of tt are:

    • x=5cos(6πt)x = 5 \cos(6\pi t)
    • y=5sin(6πt)y = 5 \sin(6\pi t)

    These answers are correct.

  4. Part (d) - Here, the formula you used for the xx-coordinate of point BB as a function of tt is: x=5cos(6πt)+10x = 5 \cos(6\pi t) + 10 However, it appears incorrect. Since BB is 10 cm to the right of AA, the correct expression should be: x=5cos(6πt)+10x = 5 \cos(6\pi t) + 10 You need to make

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Math Problem Analysis

Mathematical Concepts

Circular Motion
Angular Velocity
Trigonometry
Coordinate Geometry

Formulas

x = 5 * cos(6πt)
y = 5 * sin(6πt)
ω = 6π radians per second
x_B = 5 * cos(6πt) + 10

Theorems

Coordinate Geometry
Angular Velocity and Circular Motion

Suitable Grade Level

Grades 11-12