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Let's analyze each part of the question you answered:

1. **Part (a)** - The coordinates for point \( A \) and \( B \) are correct:
   - \( A \) at \( (2.5, 4.33) \)
   - \( B \) at \( (12.5, 0) \)

2. **Part (b)** - The angular velocity, \( \omega = 6\pi \) radians per second, is also correct.

3. **Part (c)** - The expressions for the \( x \)- and \( y \)-coordinates of point \( A \) as functions of \( t \) are:
   - \( x = 5 \cos(6\pi t) \)
   - \( y = 5 \sin(6\pi t) \)
   
   These answers are correct.

4. **Part (d)** - Here, the formula you used for the \( x \)-coordinate of point \( B \) as a function of \( t \) is:
   \[
   x = 5 \cos(6\pi t) + 10
   \]
   However, it appears incorrect. Since \( B \) is 10 cm to the right of \( A \), the correct expression should be:
   \[
   x = 5 \cos(6\pi t) + 10
   \]
   You need to make

A 10-centimeter rod is attached at one end to a point A rotating counterclockwise on a wheel of radius 5 cm. The other end B is free to move back and forth along a horizontal bar that goes through the center of the wheel. At time t=1/18 sec, the rod is situated as in the diagram. The wheel rotates counterclockwise at 3.0 revolutions per second.

Explore a physics problem involving circular motion and angular velocity with a 10-cm rod attached to a rotating wheel. Calculate coordinates, angular velocity, and velocities as functions of time. Perfect for Grades 11-12 students.

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