Math Problem Statement

(((-1)^n)(ln(n)))/n

Solution

To analyze the expression (1)nln(n)n\frac{(-1)^n \ln(n)}{n}, we can look into its behavior as nn approaches infinity and determine its convergence.

  1. Alternating Nature: The term (1)n(-1)^n indicates that the expression alternates in sign, being positive for even nn and negative for odd nn.

  2. Growth of ln(n)\ln(n): The natural logarithm ln(n)\ln(n) grows slowly compared to polynomial functions. Specifically, as nn increases, ln(n)\ln(n) increases without bound, but at a much slower rate than nn.

  3. Dominating Factor: As nn grows larger, the denominator nn will dominate the behavior of the fraction. The entire expression tends toward zero since: limnln(n)n=0.\lim_{n \to \infty} \frac{\ln(n)}{n} = 0.

  4. Convergence: Given that the terms alternate and the absolute values ln(n)n\left| \frac{\ln(n)}{n} \right| converge to 0, the series converges by the Alternating Series Test.

Conclusion

The series n=1(1)nln(n)n\sum_{n=1}^{\infty} \frac{(-1)^n \ln(n)}{n} converges.

If you would like more details or have questions about specific aspects of this series, feel free to ask!

Further Questions

  1. What are some examples of similar alternating series?
  2. Can you explain the Alternating Series Test in more detail?
  3. How does the convergence of this series compare to non-alternating series?
  4. What are other functions that behave similarly to ln(n)\ln(n) in terms of growth?
  5. Would you like to see a numerical evaluation of the first few terms of the series?

Tip: Always consider the growth rates of functions when analyzing convergence, as they can significantly influence the behavior of series.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Series Convergence
Logarithmic Functions
Alternating Series

Formulas

lim (n -> ∞) ln(n)/n = 0
Alternating Series Test

Theorems

Alternating Series Test

Suitable Grade Level

Grades 11-12