Math Problem Statement

does the sequence (((-1)^(n+1))*sqrt(n))/(n+ln(n)) converge?

Solution

We need to determine whether the sequence an=(1)n+1nn+ln(n)a_n = \frac{(-1)^{n+1} \sqrt{n}}{n + \ln(n)} converges as nn \to \infty. Let’s carefully analyze it.


Step 1: Check for Alternating Behavior

The factor (1)n+1(-1)^{n+1} causes the sequence to alternate in sign. This suggests that the sequence might converge conditionally, or diverge if the positive and negative terms do not balance properly.


Step 2: Behavior of the Absolute Value an|a_n|

To apply convergence tests, let’s first look at the absolute value of the sequence:

an=nn+ln(n).|a_n| = \frac{\sqrt{n}}{n + \ln(n)}.

We need to analyze whether this absolute value goes to 0 as nn \to \infty.

  • As nn \to \infty, the nn-term in the denominator dominates ln(n)\ln(n) because nn grows much faster than ln(n)\ln(n). Thus, the denominator behaves asymptotically like nn.

  • Therefore, the sequence behaves like:

    annn=1n.|a_n| \approx \frac{\sqrt{n}}{n} = \frac{1}{\sqrt{n}}.

  • As nn \to \infty, 1n0\frac{1}{\sqrt{n}} \to 0. This suggests that the absolute values of the terms shrink to 0.


Step 3: Alternating Series Test

Since the sequence alternates in sign, we can apply the Alternating Series Test (Leibniz’s test). The test requires:

  1. The absolute value an|a_n| should decrease monotonically (i.e., an+1<an|a_{n+1}| < |a_n| for large nn).
  2. an0|a_n| \to 0 as nn \to \infty.
  • From Step 2, we saw that an1n|a_n| \approx \frac{1}{\sqrt{n}}, which decreases monotonically and approaches 0 as nn \to \infty.

Step 4: Conclusion

Since the terms an|a_n| decrease monotonically to 0, the Alternating Series Test guarantees that the sequence an=(1)n+1nn+ln(n)a_n = \frac{(-1)^{n+1} \sqrt{n}}{n + \ln(n)} converges.


Would you like further details or additional questions about convergence or other related topics?


Five Related Questions:

  1. What is the Alternating Series Test, and when can it be applied?
  2. How does the behavior of logarithmic terms compare with polynomials for large nn?
  3. What is conditional convergence, and how is it different from absolute convergence?
  4. Can a sequence that passes the Alternating Series Test fail to be absolutely convergent?
  5. How do growth rates like ln(n)\ln(n), npn^p, and ene^n compare as nn \to \infty?

Tip:

When working with sequences involving alternating signs, always try to isolate the absolute value to simplify the analysis and then apply the Alternating Series Test if needed.

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Math Problem Analysis

Mathematical Concepts

Sequences
Convergence of Sequences
Alternating Series Test

Formulas

a_n = (-1)^{n+1} \frac{\sqrt{n}}{n + \ln(n)}
|a_n| = \frac{\sqrt{n}}{n + \ln(n)}
Asymptotic behavior: |a_n| \approx \frac{1}{\sqrt{n}}

Theorems

Alternating Series Test (Leibniz's Test)

Suitable Grade Level

University-level Calculus