Infinite Alternating Series with Logarithms

Math Problem Statement

Summation of the series: ∑((-1)^(n+1))/(log(n+1)) from n=1 to ∞.

The expression you've provided is a series:

$\sum_{n=1}^\infty \frac{(-1)^{n+1}}{\log(n+1)}$

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Infinite Series
Alternating Series
Logarithms

Summation formula: ∑((-1)^(n+1))/(log(n+1))
Properties of logarithms

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Convergence of Infinite Series

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