Math Problem Statement

Evaluate the contour integral \( \int_C \frac{z^2 + 9}{z - 4i} \, dz \), where \( C \) is parameterized by \( z(t) = 3i + 2e^{it} \) for \( t \in [-\pi, \pi] \). The integral is given as \( -14\pi i \).

Solution

The problem describes a contour integral of a complex function z2+9z4i\frac{z^2 + 9}{z - 4i} along a curve CC, which is parameterized as z(t)=3i+2eitz(t) = 3i + 2e^{it} for t[π,π]t \in [-\pi, \pi]. The integral is given as:

Cz2+9z4idz=14πi\int_C \frac{z^2 + 9}{z - 4i} \, dz = -14\pi i


Steps to Solve:

  1. Understand the parameterization:
    The contour CC is a circle in the complex plane, centered at 3i3i with radius 2. The parameterization is z(t)=3i+2eitz(t) = 3i + 2e^{it}, which traces the circle once counterclockwise as tt varies from π-\pi to π\pi.

  2. Singularity inside the contour:
    The function z2+9z4i\frac{z^2 + 9}{z - 4i} has a singularity at z=4iz = 4i because of the term 1z4i\frac{1}{z - 4i}.

    • To determine whether 4i4i lies inside the contour, compute its distance to the center 3i3i:
      4i3i=1|4i - 3i| = 1
      Since the radius of the contour is 2, 4i4i lies inside the contour.
  3. Apply the residue theorem:
    The integral of a meromorphic function around a closed contour is given by: Cf(z)dz=2πi(Residue of f(z) at singularity inside C).\int_C f(z) \, dz = 2\pi i \cdot \text{(Residue of } f(z) \text{ at singularity inside } C). Here, f(z)=z2+9z4if(z) = \frac{z^2 + 9}{z - 4i}. The residue at z=4iz = 4i is: Residue=limz4i(z4i)f(z)=limz4iz2+9z4i(z4i)=z2+9z=4i.\text{Residue} = \lim_{z \to 4i} (z - 4i) \cdot f(z) = \lim_{z \to 4i} \frac{z^2 + 9}{z - 4i} \cdot (z - 4i) = z^2 + 9 \bigg|_{z = 4i}.

  4. Compute the residue:
    Substitute z=4iz = 4i into z2+9z^2 + 9: z2=(4i)2=16,z2+9=16+9=7.z^2 = (4i)^2 = -16, \quad z^2 + 9 = -16 + 9 = -7. Thus, the residue is: 7.-7.

  5. Evaluate the integral:
    Using the residue theorem: Cz2+9z4idz=2πi(7)=14πi.\int_C \frac{z^2 + 9}{z - 4i} \, dz = 2\pi i \cdot (-7) = -14\pi i.

This matches the given result, confirming the calculation.


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Related Questions:

  1. What is the residue theorem, and how is it applied in complex analysis?
  2. How do you parameterize other common contours in the complex plane?
  3. Why does the residue theorem work only for meromorphic functions?
  4. Can a contour integral be evaluated without using the residue theorem? If yes, how?
  5. How would the result change if the singularity 4i4i were outside the contour?

Tip:

Always verify whether singularities lie inside or outside the contour before applying the residue theorem. This step is crucial to avoid errors in evaluation!

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Math Problem Analysis

Mathematical Concepts

Complex Analysis
Residue Theorem
Contour Integration

Formulas

Residue Theorem: \( \int_C f(z) \, dz = 2\pi i \cdot \text{Res}[f(z)] \)
Residue Formula: \( \text{Res}[f(z), z_0] = \lim_{z \to z_0} (z - z_0) f(z) \)

Theorems

Residue Theorem

Suitable Grade Level

Undergraduate Mathematics