Math Problem Statement

What is the common ratio of the geometric sequence below?

18,-6,2,-2/3..

Solution

To find the common ratio rr of a geometric sequence, we divide any term by the preceding term.

The terms of the sequence are:

18,6,2,23,18, -6, 2, -\frac{2}{3}, \dots

Let's calculate the common ratio step by step:

  1. Divide the second term by the first term: r=618=13r = \frac{-6}{18} = -\frac{1}{3}

  2. Divide the third term by the second term: r=26=13r = \frac{2}{-6} = -\frac{1}{3}

  3. Divide the fourth term by the third term: r=232=13r = \frac{-\frac{2}{3}}{2} = -\frac{1}{3}

Since the ratio between consecutive terms is the same, the common ratio is: r=13r = -\frac{1}{3}

Would you like further details on how to work with geometric sequences?

Here are some related questions:

  1. How do you find the nth term of a geometric sequence?
  2. How do you determine the sum of a geometric series?
  3. What are the conditions for the convergence of an infinite geometric series?
  4. How does the common ratio affect the growth or decay of a geometric sequence?
  5. How can you find the common ratio if not all terms of the sequence are given?

Tip: In geometric sequences, if the common ratio is negative, the terms alternate between positive and negative.

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Math Problem Analysis

Mathematical Concepts

Geometric Sequences
Ratios

Formulas

Common ratio formula: r = a_n / a_(n-1)

Theorems

Geometric Sequence Theorem

Suitable Grade Level

Grades 8-10