Math Problem Statement

Find the sum of the first five terms of the geometric sequence with a₁ = 2 and r = -6.

Solution

We are given a geometric sequence where a1=2a_1 = 2 and the common ratio r=6r = -6. We need to find the sum of the first five terms.

The formula for the sum SnS_n of the first nn terms of a geometric sequence is:

Sn=a1(1rn)1r(for r1)S_n = \frac{a_1(1 - r^n)}{1 - r} \quad \text{(for } r \neq 1 \text{)}

For this problem:

  • a1=2a_1 = 2
  • r=6r = -6
  • n=5n = 5

Substituting these values into the formula:

S5=2(1(6)5)1(6)S_5 = \frac{2(1 - (-6)^5)}{1 - (-6)}

Now, I'll calculate the exact sum.The sum of the first five terms of the geometric sequence is 2,2222,222.

Would you like further details on this solution, or do you have any other questions?

Here are 5 related questions to consider:

  1. How would the sum change if the common ratio rr were positive?
  2. What is the formula for the sum if nn is not given and we have to compute indefinitely many terms?
  3. How does changing a1a_1 affect the sum of the sequence?
  4. Can you explain the difference between arithmetic and geometric sequences?
  5. What would happen if the common ratio r=1r = 1?

Tip: When working with geometric sequences, if the absolute value of the ratio r|r| is greater than 1, the terms grow (or shrink) rapidly.

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Math Problem Analysis

Mathematical Concepts

Geometric Sequences
Series

Formulas

Sum of first n terms of a geometric sequence: Sₙ = a₁(1 - rⁿ) / (1 - r)

Theorems

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Suitable Grade Level

Grades 9-12