Math Problem Statement

In the figure, ABCD is a circle. It is given that CA = CB and ∠ADB = 70°. Find ∠BDC.

Solution

Let's walk through the problems from the image one by one.

Problem 1

In the circle ABCDABCD:

  • It is given that CA=CBCA = CB and ADB=70\angle ADB = 70^\circ.

(a) Find BDC\angle BDC.

The key insight here is that triangle ADBADB is isosceles since CA=CBCA = CB. Also, note that ADB\angle ADB is the angle subtended by arc ABAB, and we can apply the properties of cyclic quadrilaterals and isosceles triangles.

Problem 2

In the circle ABCDEABCDE:

  • It is given that ABECAB \parallel EC, DAE=70\angle DAE = 70^\circ, and CED=30\angle CED = 30^\circ.
  • ADAD and CECE intersect at FF.

You need to find expressions for mm and kk in terms of θ\theta. Here, you can apply the properties of alternate angles, and the intersecting chords theorem will help express the angles in terms of θ\theta.

Problem 3

In the circle ABCDEABCDE:

  • BEBE is the diameter of the circle, and it is given that AB=CDAB = CD and BC:CD=1:3BC : CD = 1:3.
  • Let BDC=α\angle BDC = \alpha.

(a) Express CBD\angle CBD, BCD\angle BCD, and ABD\angle ABD in terms of α\alpha.

The key step involves using the fact that BEBE is the diameter, which means BAE=90\angle BAE = 90^\circ. You can then express the required angles by using the angle subtended by the same arc property.

(b)(i) Express ABE\angle ABE in terms of α\alpha.

Here, you'll apply the cyclic property and the given ratios to find the expression.

(b)(ii) It is given that GG is the in-centre of ABD\triangle ABD, and Danny claims that GG lies on BEBE.

You need to determine whether GG, the in-centre, lies on the diameter BEBE. This can be checked by investigating whether the in-centre (which is where angle bisectors meet) is aligned with the properties of the diameter.


Would you like to go into the details of any specific part of these problems? Let me know if you want a full solution for one of them, or if you'd like further clarification!


Here are 5 questions based on this:

  1. What is the significance of the property CA=CBCA = CB in ADB\triangle ADB?
  2. How do cyclic quadrilateral properties help in solving BDC\angle BDC?
  3. What theorem can be applied to find mm and kk in Problem 2?
  4. How do we use the given ratio BC:CD=1:3BC : CD = 1:3 in Problem 3?
  5. Why is the in-centre of a triangle significant for proving Danny's claim in Problem 3(b)(ii)?

Tip: Always start by identifying key geometric properties like parallel lines or diameters in a circle, as these often unlock the solution through theorems like alternate angles or the angle subtended by the diameter.

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Math Problem Analysis

Mathematical Concepts

Circle Theorems
Isosceles Triangle
Cyclic Quadrilateral

Formulas

Angle subtended by the same arc
Angle at the centre is twice the angle at the circumference

Theorems

Isosceles triangle properties
Cyclic quadrilateral theorem

Suitable Grade Level

Grades 10-12