Math Problem Statement

The diagram shows a circle, center O, passing through points A, B, C, and D. BOD is a straight line, and angle BAC = 38°. The line BQ is a tangent to the circle at B. Find (a) angle DAC, (b) angle DBC, (c) angle CBQ.

Solution

Let's analyze the geometry problem step by step based on the provided diagram and the description.

Given Information:

  • The circle has a center OO and passes through points AA, BB, CC, and DD.
  • BODBOD is a straight line.
  • BAC=38\angle BAC = 38^\circ.
  • The line BQBQ is a tangent to the circle at point BB.

Required:

  1. DAC\angle DAC
  2. DBC\angle DBC
  3. CBQ\angle CBQ

(a) DAC\angle DAC

We know that BAC=38\angle BAC = 38^\circ, and from the property of a circle, angles subtended by the same arc are equal. Since both DAC\angle DAC and BAC\angle BAC are subtended by the same arc ACAC, we can conclude:

DAC=BAC=38\angle DAC = \angle BAC = 38^\circ

(b) DBC\angle DBC

To find DBC\angle DBC, we need to use the fact that BOD\angle BOD is a straight line. In a circle, the angle at the center is twice the angle subtended on the circumference. Therefore, using this property for arc BDBD, we have:

BOD=2×BCD\angle BOD = 2 \times \angle BCD

Given that BODBOD is a straight line, BOD=180\angle BOD = 180^\circ. Thus:

180=2×BCD180^\circ = 2 \times \angle BCD

Solving for BCD\angle BCD:

BCD=1802=90\angle BCD = \frac{180^\circ}{2} = 90^\circ

Therefore, DBC\angle DBC is:

DBC=90\angle DBC = 90^\circ

(c) CBQ\angle CBQ

Finally, BQBQ is a tangent to the circle at BB. By the tangent-secant theorem, the angle between the tangent and a chord is equal to the angle subtended by the chord on the opposite side of the circle. In this case, the chord is BCBC, and the angle subtended by BCBC at AA is BAC=38\angle BAC = 38^\circ. Hence:

CBQ=BAC=38\angle CBQ = \angle BAC = 38^\circ


Final Answers:

(a) DAC=38\angle DAC = 38^\circ
(b) DBC=90\angle DBC = 90^\circ
(c) CBQ=38\angle CBQ = 38^\circ

Would you like further explanation or have any questions about this solution?


Related Questions:

  1. What is the relationship between the tangent and the radius at the point of contact in a circle?
  2. How do we calculate the angles subtended by the same arc in a circle?
  3. What is the cyclic quadrilateral property, and how does it apply to this problem?
  4. How would the solution change if BAC\angle BAC were different?
  5. Can you explain the tangent-secant theorem in more detail?

Tip: In a circle, the angle subtended by an arc at the center is always double the angle subtended at any point on the circumference.

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Math Problem Analysis

Mathematical Concepts

Circle Geometry
Angles subtended by the same arc
Tangent-secant theorem

Formulas

Angles subtended by the same arc are equal
Angle at the center is twice the angle subtended at the circumference
Angle between a tangent and a chord equals the angle subtended by the chord on the opposite side

Theorems

Tangent-secant theorem
Angle subtended by the same arc
Cyclic quadrilateral properties

Suitable Grade Level

Grades 9-10