Math Problem Statement

दिए गए चित्र में, AB = AC तथा ∠ABC = 50° हो, तो ∠BDC की माप होगी?

Solution

The image you uploaded shows a geometrical problem involving a circle and triangle with given conditions.

Let's break it down:

  • ABC\triangle ABC is an isosceles triangle because AB=ACAB = AC.
  • The given angle ABC=50\angle ABC = 50^\circ.
  • The task is to find the measure of BDC\angle BDC.

Step-by-step approach:

  1. Since ABC\triangle ABC is isosceles, ACB=ABC=50\angle ACB = \angle ABC = 50^\circ.
  2. The angle ABC\angle ABC is subtended by the arc ACAC, and by the inscribed angle theorem, the angle subtended by the same arc on the circle will be half of ABC\angle ABC, which leads to the relation for BDC\angle BDC.

I will now calculate BDC\angle BDC.

Let's calculate it:We are given the following information:

  • AB=ACAB = AC (isoceles triangle),
  • ABC=50\angle ABC = 50^\circ.

Since AB=ACAB = AC, the angles ABC\angle ABC and ACB\angle ACB are equal, so: ACB=50.\angle ACB = 50^\circ.

Next, the total sum of angles in any triangle is 180180^\circ. Therefore, in ABC\triangle ABC: BAC+ABC+ACB=180.\angle BAC + \angle ABC + \angle ACB = 180^\circ. Substituting the known values: BAC+50+50=180,\angle BAC + 50^\circ + 50^\circ = 180^\circ, BAC+100=180,\angle BAC + 100^\circ = 180^\circ, BAC=180100=80.\angle BAC = 180^\circ - 100^\circ = 80^\circ.

Now, let's focus on BDC\angle BDC, which is the angle subtended by arc BCBC. By the inscribed angle theorem, the angle subtended by an arc at the circumference is half of the central angle subtended by the same arc.

The central angle subtended by arc BCBC is 2×BAC=2×80=1602 \times \angle BAC = 2 \times 80^\circ = 160^\circ.

Thus, the inscribed angle BDC\angle BDC, which subtends the same arc, is: BDC=1602=80.\angle BDC = \frac{160^\circ}{2} = 80^\circ.

So, the measure of BDC\angle BDC is 8080^\circ.

Let me know if you need further clarification or details!

Here are 5 related questions:

  1. What is the inscribed angle theorem, and how does it apply in this case?
  2. How can you prove that a triangle inscribed in a circle has a total of 180°?
  3. What other properties of isosceles triangles can help solve geometric problems like this one?
  4. How does the central angle relate to the inscribed angle in a circle?
  5. What are some real-world examples of inscribed angles in geometry?

Tip: Always remember that the sum of angles in any triangle is 180°, and use the properties of circles to relate central and inscribed angles!

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Math Problem Analysis

Mathematical Concepts

Geometry
Inscribed Angles
Isosceles Triangle
Angle Sum Property

Formulas

Sum of angles in a triangle = 180°
Inscribed angle theorem

Theorems

Inscribed angle theorem
Angle sum property of a triangle

Suitable Grade Level

Grades 9-11