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The image contains a set of multiple-choice capacitor-related problems in Bengali. I'll walk you through solving a few of them.

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**Problem 205:**
Two capacitors with capacitances of 4.4 µF and 8 µF are connected in parallel with a 100V battery. What is the total charge stored by the capacitors?

**Solution:**
In a parallel combination, the total charge \( Q_{\text{total}} \) is given by:
\[
Q_{\text{total}} = C_{\text{total}} \times V
\]
Where \( C_{\text{total}} = C_1 + C_2 \) (since it's a parallel circuit).

1. \( C_1 = 4.4 \, \mu F = 4.4 \times 10^{-6} \, F \)
2. \( C_2 = 8 \, \mu F = 8 \times 10^{-6} \, F \)
3. \( V = 100 \, V \)

Now, 
\[
C_{\text{total}} = 4.4 \times 10^{-6} + 8 \times 10^{-6} = 12.4 \times 10^{-6} \, F
\]
Then, the total charge \( Q_{\text{total}} \):
\[
Q_{\text{total}} = 12.4 \times 10^{-6} \times 100 = 12.4 \times 10^{-4} \, C = 1.24 \times 10^{-3} \, C = 12.4 \, mC
\]

So, the closest answer seems to match **option (3)**.

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Would you like to proceed with more problems or need further explanation?

Here are five related questions for further exploration:

1. How do capacitors behave differently when arranged in series versus parallel?
2. What is the formula for calculating the equivalent capacitance in series?
3. How does the stored energy in a capacitor change with voltage?
4. Why is the total charge different in series versus parallel connections?
5. What is the physical meaning of capacitance?

**Tip:** Remember that the capacitance in parallel adds up, whereas in series, the reciprocal sum determines the total capacitance.

205.4 µF and 8 µF capacitors are connected with a 100V battery in parallel. What is the total charge stored by the capacitors?

Learn how to calculate the total charge stored by two capacitors (4.4 µF and 8 µF) connected in parallel with a 100V battery. This example covers key concepts of capacitance in parallel circuits and the formula for charge calculation. Suitable for high school students in Grades 10-12.

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