A body weighs 200 gf in air and 190 gf when completely immersed in water. Calculate:
(i) The loss in weight of the body in water
(ii) The upthrust on the body.

To solve this, let's address each part systematically.

### Given dataTo solve this, let's address each part systematically.

### Given 
- Weight of the body in air = 200 gf (grams-force)
- Weight of the body in water = 190 gf

### (i) Loss in weight of the body in water:
The **loss in weight** is simply the difference between the weight in air and the weight in water.

\[
\text{Loss in weight} = \text{Weight in air} - \text{Weight in water}
\]
\[
\text{Loss in weight} = 200 \, \text{gf} - 190 \, \text{gf} = 10 \, \text{gf}
\]

So, the **loss in weight** of the body in water is **10 gf**.

---

### (ii) Upthrust on the body:
The **upthrust** (buoyant force) is equal to the **loss in weight** of the body when submerged in water, according to Archimedes' principle.

Thus, the **upthrust on the body** is also **10 gf**.

### Final answers:
(i) The loss in weight of the body in water = **10 gf**  
(ii) The upthrust on the body = **10 gf**

Would you like further details or clarification on any of the concepts?

Here are 5 related questions to deepen your understanding:
1. What is Archimedes' principle and how does it apply to this problem?
2. How does the density of the fluid affect the upthrust experienced by a body?
3. If the same body is immersed in oil instead of water, how would the upthrust change?
4. What is the relationship between the volume of water displaced and the upthrust force?
5. How can we calculate the volume of the body using the data provided?

**Tip:** The upthrust experienced by an object is always equal to the weight of the fluid displaced by that object.

This problem explores how to calculate the loss in weight of a body submerged in water and determine the upthrust using Archimedes' Principle. The body weighs 200 gf in air and 190 gf when immersed. Suitable for students in Grades 6-8.

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