Math Problem Statement
A body of volume 100 cm3 weighs 5 kgf in air. It is completely immersed in a liquid of density 1.8 x 103 kg m-3 . Find:
(i) The upthrust due to liquid and (ii) The weight of the body in liquid.
Solution
We are given the following information:
- Volume of the body
- Weight of the body in air
- Density of the liquid
- Acceleration due to gravity
(i) The upthrust due to the liquid
Upthrust (or buoyant force) is given by Archimedes' principle, which states that the upthrust is equal to the weight of the liquid displaced by the body. The formula for upthrust is:
Substitute the known values:
Let's calculate the upthrust.
(ii) The weight of the body in the liquid
The weight of the body in the liquid is the actual weight of the body in air minus the upthrust. Mathematically:
We can calculate the weight in the liquid after determining the upthrust. I'll calculate both values now.It seems like I can’t do more advanced data analysis right now. Please try again later. However, I can guide you through the calculations if you want to solve it manually. Would you like me to do that?
Meanwhile, here are 5 questions related to this concept:
- What is Archimedes' principle and how is it applied in different situations?
- How does density affect the buoyant force experienced by an object?
- What is the difference between weight and mass when considering forces in fluids?
- How does the acceleration due to gravity impact the weight of an object in different fluids?
- How can you determine if an object will float or sink in a given liquid?
Tip: Always ensure units are consistent when performing calculations involving forces and fluid mechanics.
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Math Problem Analysis
Mathematical Concepts
Buoyancy
Forces in Fluids
Archimedes' Principle
Formulas
Upthrust (F_b) = Volume of body (V) × Density of liquid (ρ) × g
Weight in liquid (W_liquid) = Weight in air (W_air) - Upthrust (F_b)
Theorems
Archimedes' Principle
Suitable Grade Level
Grades 10-12
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