 Blake is participating in a hydrostatic weighing test. His body weight on dry land is 175 lbs, and his weight in water is 8 lbs. Calculate Blake's body volume. Round your answer to the first decimal place.
Group of answer choices
167 lbs
183 lbs
100 lbs
89 lbs


To find Blake's body volume using the hydrostatic weighing test, we need to apply the principle of Archimedes. According to this principle, the buoyant force acting on Blake when submerged in water equals the weight of the water displaced by his body. 

**Step 1: Calculate the weight of water displaced.**

The weight of the water displaced is equal to the difference between Blake's dry weight and his underwater weight:
\[
\text{Weight of water displaced} = 175 \text{ lbs} - 8 \text{ lbs} = 167 \text{ lbs}
\]

**Step 2: Convert the weight of the water displaced to volume.**

Since the density of water is approximately 62.4 lbs/ft³, we can calculate the volume of water displaced (which is equal to Blake's body volume):
\[
\text{Body volume} = \frac{\text{Weight of water displaced}}{\text{Density of water}} = \frac{167 \text{ lbs}}{62.4 \text{ lbs/ft}^3} \approx 2.677 \text{ ft}^3
\]

Rounding to the first decimal place gives:
\[
\text{Blake's body volume} \approx 2.7 \text{ ft}^3
\]

Therefore, the body volume should be rounded correctly

Blake is participating in a hydrostatic weighing test. His body weight on dry land is 175 lbs, and his weight in water is 8 lbs. Calculate Blake's body volume. Round your answer to the first decimal place.

Learn how to calculate body volume using hydrostatic weighing based on Archimedes' Principle. This example uses Blake's weights on dry land and in water, with a step-by-step solution involving buoyancy and density. Ideal for high school students in Grades 10-12.

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