The given problem asks to find how long it takes for a free-falling object to reach the ground when dropped from a height of 360 feet. The formula provided is:

$t = \sqrt{\frac{h}{16}}$

where:

• $t$ is the time in seconds,
• $h$ is the height in feet,
• 16 is a constant related to the acceleration due to gravity in feet per second squared.

We are asked to find the time $t$ when $h = 360$ feet.

Let's calculate the time using the formula.

$t = \sqrt{\frac{360}{16}}$

I'll compute this for you.The time it takes for the object to reach the ground from a height of 360 feet is approximately 4.7 seconds (rounded to the nearest tenth).

Do you need further explanation or details on this?

Here are five related questions you might find helpful:

1. How would the formula change if the object is dropped from a different height, say 500 feet?
2. What assumptions does this formula make about air resistance and other external forces?
3. How does this formula compare to using the full gravitational equation for motion?
4. How would the time change if this were on a different planet with a different gravitational constant?
5. How would you modify this equation for an object thrown upwards first?

Tip: Remember, the constant 16 in this equation is derived from approximating gravity as 32 feet per second squared, divided by 2.