An object is dropped from a high height. How long will it take the falling object to reach an instantaneous velocity of 160​ feet per second, assuming wind resistance is negligible?

To find how long it takes for the object to reach an instantaneous velocity of 160 feet per second, we can use the following kinematic equation for velocity under free fall:

\[
v = g \cdot t
\]

Where:
- \(v\) is the velocity (160 feet per second),
- \(g\) is the acceleration due to gravity (32 feet per second squared on Earth),
- \(t\) is the time in seconds.

Now, solve for \(t\):

\[
t = \frac{v}{g}
\]

Substitute the given values:

\[
t = \frac{160}{32} = 5 \text{ seconds}
\]

Thus, it will take 5 seconds for the object to reach a velocity of 160 feet per second.

Would you like more details or have any questions?

Here are 5 related questions:
1. How far will the object have fallen after 5 seconds?
2. What would be the velocity after 10 seconds of free fall?
3. How would air resistance affect the fall time and velocity?
4. What is the velocity of the object after 2 seconds of free fall?
5. How long would it take for the object to fall 500 feet?

**Tip:** Remember that in real-life situations, air resistance plays a significant role in limiting the maximum velocity, also known as terminal velocity.

Find out how long it takes for an object to reach 160 feet per second in free fall using kinematic equations. This problem explores the formula v = g * t and is suitable for high school students studying physics and kinematics.

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