To find the force Peter exerted to overcome static friction, we can use Newton's second law of motion, which states:

$F = ma$

Where:

• $F$ is the force exerted,
• $m$ is the mass of the object,
• $a$ is the acceleration.

Given:

• $m = 24 \, \text{kg}$
• $a = 6.2 \, \text{m/s}^2$

Now, substitute the given values into the formula:

$F = 24 \, \text{kg} \times 6.2 \, \text{m/s}^2$

$F = 148.8 \, \text{N}$

So, Peter exerted a force of 148.8 N to overcome static friction.

Would you like more details on this calculation or have any other questions?

Here are 5 related questions you might find interesting:

1. What is static friction and how does it differ from kinetic friction?
2. How would the force change if the mass of the box increased?
3. What role does the coefficient of friction play in determining the required force?
4. How would the acceleration change if Peter exerted a larger force?
5. Can you calculate the work done by Peter in moving the box a certain distance?

Tip: Always ensure you are using the correct units in physics problems to avoid errors in calculations.