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The problem asks how much force is required to move a 20 kg box up a ramp with an acceleration of 9 m/s². 

We can solve this using Newton's second law of motion, which states:

\[
F = m \cdot a
\]

Where:
- \( F \) is the force,
- \( m \) is the mass of the box (20 kg),
- \( a \) is the acceleration (9 m/s²).

Substituting the given values:

\[
F = 20 \, \text{kg} \times 9 \, \text{m/s}^2 = 180 \, \text{N}
\]

Thus, the required force is **180 N**.

Would you like a more detailed explanation, or do you have any further questions?

Here are 5 related questions for further exploration:
1. How would friction affect the required force?
2. What happens if the ramp is inclined at an angle? How does it change the force?
3. How would the force change if the mass of the box were doubled?
4. What is the difference between net force and applied force in this scenario?
5. How would the force change if the acceleration were halved?

**Tip**: Always include the effects of gravity when considering forces on a ramp, especially if the angle of the incline is known.

How much force would it take to move a 20 kg box up a ramp with an acceleration of 9 m/s²?

Learn how to calculate the force required to move a 20 kg box up a ramp with an acceleration of 9 m/s² using Newton's Second Law of Motion. The step-by-step solution shows how to apply F = m * a to find the force in this scenario, suitable for high school students.

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