Math Problem Statement

A 10-kg box is held in place by an applied force F on a rough wall inside a train car. The coefficient of static friction between the box and the wall is 0.20. If the train accelerates at 5.0 m/s², what must the magnitude of the applied force F be to hold the box in place without sliding?

Solution

This is a physics problem involving forces and friction, specifically static friction, on a 10-kg box inside a moving train. Let's break it down step by step:

Problem details:

  • Mass of the box: m=10kgm = 10 \, \text{kg}
  • Acceleration of the train: a=5.0m/s2a = 5.0 \, \text{m/s}^2
  • Coefficient of static friction between the box and the wall: μs=0.20\mu_s = 0.20
  • Gravity: g=9.8m/s2g = 9.8 \, \text{m/s}^2

Goal:

Find the magnitude of the applied force FF to hold the box in place without sliding. The force FF presses the box against the wall, and static friction keeps it from sliding down.

Forces acting on the box:

  1. Gravitational force pulling the box down: Fg=mg=109.8=98NF_g = m \cdot g = 10 \cdot 9.8 = 98 \, \text{N}

  2. Normal force is provided by the force FF, which is applied horizontally to press the box against the wall.

  3. Static friction force acts upward to counteract the gravitational force. The maximum static friction force is: fs=μsFNf_s = \mu_s \cdot F_N where FNF_N is the normal force, and in this case, FN=FF_N = F (the force applied horizontally).

  4. The box is also accelerating horizontally with the train, so there is a horizontal force FF required to cause that acceleration.

Vertical force balance:

For the box to stay in place (not slide down), the static friction must balance the weight: fs=Fgf_s = F_g Thus, μsF=Fg    0.20F=98\mu_s \cdot F = F_g \implies 0.20 \cdot F = 98 Solving for FF: F=980.20=490NF = \frac{98}{0.20} = 490 \, \text{N}

Conclusion:

The required force FF is approximately 490N490 \, \text{N}. The closest answer is (C) 500 N.

Would you like more details on any part of this explanation?

Follow-up questions:

  1. How would the answer change if the coefficient of friction was higher or lower?
  2. What if the train were accelerating at a different rate, say 2.5 m/s²?
  3. How would the normal force change if the mass of the box increased to 20 kg?
  4. What is the role of static friction in other real-world scenarios, such as keeping a book on a sloped surface?
  5. How does the direction of the applied force affect the friction and normal force?

Tip:

Always draw a free-body diagram in physics problems involving forces to visualize how different forces interact.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Newton's Laws of Motion
Static Friction
Forces in Physics

Formulas

Force of gravity: F_g = m * g
Static friction: f_s = μ_s * F_N
Normal force: F_N = F

Theorems

Newton's Second Law: F = m * a
Static friction theorem

Suitable Grade Level

Grades 11-12