Math Problem Statement

Given a mean, standard deviation, and a raw score, find the corresponding z-score. Assume the distribution is normal. Mean 80, standard deviation 5.8, x = 94.

Solution

To solve for the corresponding z-score, we use the formula for the z-score:

z=xμσz = \frac{x - \mu}{\sigma}

Where:

  • x=94x = 94 (the raw score),
  • μ=80\mu = 80 (the mean),
  • σ=5.8\sigma = 5.8 (the standard deviation).

Substituting the values into the formula:

z=94805.8=145.82.414z = \frac{94 - 80}{5.8} = \frac{14}{5.8} \approx 2.414

So, the corresponding z-score is approximately z=2.414z = 2.414.

Would you like more details or further clarification? Here are some related questions to explore:

  1. What is the interpretation of a z-score of 2.414 in a normal distribution?
  2. How would you calculate the probability associated with this z-score?
  3. What is the significance of a positive vs. a negative z-score?
  4. How would the z-score change if the standard deviation were larger?
  5. How does the z-score relate to percentiles in a normal distribution?

Tip: The z-score tells you how many standard deviations a data point is from the mean.