Math Problem Statement

Given an Audio with sampling rate at 44.1KHz and Height of each sample saved as 16-bit number for high-fidelity recordings, what would be the physical storing space for 1-minute raw WAV audio format?

Solution

To calculate the storage space required for a 1-minute raw WAV audio file, we need to consider the following details provided in the question:

  1. Sampling Rate: 44.1 kHz (44,100 samples per second)
  2. Bit Depth (Height): 16-bit (each sample uses 16 bits, or 2 bytes)
  3. Duration: 1 minute (60 seconds)
  4. Channels: This information is not provided, so we will assume it's a mono (1 channel) recording unless stereo (2 channels) is specified.

Formula:

The total storage requirement for the WAV file can be calculated as:

File Size (in bytes)=Sampling Rate×Bit Depth (in bytes)×Channels×Duration (in seconds)\text{File Size (in bytes)} = \text{Sampling Rate} \times \text{Bit Depth (in bytes)} \times \text{Channels} \times \text{Duration (in seconds)}

For Mono (1 channel):

File Size=44,100samples/second×2bytes/sample×1channel×60seconds\text{File Size} = 44,100 \, \text{samples/second} \times 2 \, \text{bytes/sample} \times 1 \, \text{channel} \times 60 \, \text{seconds} File Size=44,100×2×60=5,292,000bytes\text{File Size} = 44,100 \times 2 \times 60 = 5,292,000 \, \text{bytes}

Converting to megabytes (1 MB = 1,048,576 bytes): File Size5,292,0001,048,5765.05MB\text{File Size} \approx \frac{5,292,000}{1,048,576} \approx 5.05 \, \text{MB}

For Stereo (2 channels):

File Size=44,100×2bytes/sample×2channels×60\text{File Size} = 44,100 \times 2 \, \text{bytes/sample} \times 2 \, \text{channels} \times 60 File Size=44,100×2×2×60=10,584,000bytes\text{File Size} = 44,100 \times 2 \times 2 \times 60 = 10,584,000 \, \text{bytes}

Converting to megabytes: File Size10,584,0001,048,57610.09MB\text{File Size} \approx \frac{10,584,000}{1,048,576} \approx 10.09 \, \text{MB}

Summary:

  • For Mono: The file size is approximately 5.05 MB.
  • For Stereo: The file size is approximately 10.09 MB.

Would you like more details on the calculations or additional clarification?

Related Questions:

  1. What is the difference between mono and stereo WAV files?
  2. How does the bit depth affect the quality and file size of audio?
  3. What is the role of compression in reducing the file size of audio files like MP3?
  4. How does increasing the sampling rate impact audio quality and file size?
  5. How can we calculate the storage for other durations of audio?

Tip: WAV files are uncompressed, which means they retain high audio quality but take up more storage than compressed formats like MP3 or AAC.

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Math Problem Analysis

Mathematical Concepts

Digital Audio
Sampling Rate
Bit Depth
Storage Calculation

Formulas

File Size (in bytes) = Sampling Rate × Bit Depth (in bytes) × Channels × Duration (in seconds)
1 MB = 1,048,576 bytes

Theorems

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Suitable Grade Level

Grades 9-12