The amount of water needed to fill an Olympic swimming pool can be calculated using the formula for the volume of a rectangular prism:

$\text{Volume} = \text{length} \times \text{width} \times \text{depth}$

Given:

• Length = 50 meters
• Width = 25 meters
• Depth = 4 meters

Substitute these values into the formula:

$\text{Volume} = 50 \, \text{m} \times 25 \, \text{m} \times 4 \, \text{m}$

$\text{Volume} = 5000 \, \text{m}^3$

So, the amount of water required to fill the pool is 5,000 cubic meters (m³).

Since 1 cubic meter equals 1,000 liters, this is equivalent to:

$5,000 \, \text{m}^3 \times 1,000 \, \text{liters/m}^3 = 5,000,000 \, \text{liters}$

Therefore, 5,000,000 liters of water are needed to fill the Olympic swimming pool.

Would you like further details or have any other questions?

Here are 5 related questions to explore further:

1. How much water is needed if the depth of the pool increases by 1 meter?
2. What is the surface area of the Olympic swimming pool?
3. How long would it take to fill the pool using a hose with a flow rate of 1,000 liters per minute?
4. How much would the weight of the water be if the pool is filled completely?
5. If the pool was half-full, how much water would it contain?

Tip: Always double-check your units when solving volume problems to avoid miscalculations!