The question is asking for the maximum volume of water that the pool can hold. We are given the pool's dimensions as follows:

• Length ($L$) = 10 meters
• Width ($W$) = 4 meters
• Depth ($D$) = 1.2 meters

The volume $V$ of a rectangular prism, such as this pool, can be calculated using the formula:

$V = L \times W \times D$

Substituting the given values:

$V = 10 \, \text{m} \times 4 \, \text{m} \times 1.2 \, \text{m} = 48 \, \text{m}^3$

Therefore, the pool can hold a maximum of 48 cubic meters of water.

Would you like more details or have any questions?

Here are 5 related questions that expand on this topic:

1. How would the volume change if the pool's depth increased to 2 meters?
2. What is the surface area of the pool's water surface?
3. If 1 cubic meter of water weighs approximately 1000 kg, how much would the water weigh when the pool is full?
4. How would the volume be affected if the width was reduced to 3 meters?
5. How much time would it take to fill this pool if water flows at a rate of 2 cubic meters per minute?

Tip: For any rectangular pool, you can calculate the volume by multiplying length, width, and depth.