To find the velocity of the ball at the end of 6.00 seconds, we can use the same equation of motion:

$v = v_0 + at$

Given:

• $v_0 = 2.72 \, \text{m/s}$ (initial velocity),
• $a = -0.629 \, \text{m/s}^2$ (acceleration),
• $t = 6.00 \, \text{s}$ (time).

Substituting these values:

$v = 2.72 + (-0.629) \times 6.00$

Let's calculate this.The velocity of the ball at the end of 6.00 seconds is approximately $-1.05 \, \text{m/s}$. The negative sign indicates that the ball is moving in the opposite direction (downhill).

Would you like more details or have any questions?

Here are some related questions you might explore:

1. How long will it take for the ball to come to a complete stop?
2. What distance does the ball travel during the 6.00 seconds?
3. What would be the velocity if the acceleration were doubled?
4. What is the total change in velocity after 6.00 seconds?
5. How would a positive acceleration affect the ball's motion?

Tip: A negative final velocity means the ball has reversed its direction.