Assuming this acceleration continues for 6.00 s, what will be its velocity at the end of this time period?(Include a – sign if applicable.)

To find the velocity of the ball at the end of 6.00 seconds, we can use the same equation of motion:

\[
v = v_0 + at
\]

Given:
- \( v_0 = 2.72 \, \text{m/s} \) (initial velocity),
- \( a = -0.629 \, \text{m/s}^2 \) (acceleration),
- \( t = 6.00 \, \text{s} \) (time).

Substituting these values:

\[
v = 2.72 + (-0.629) \times 6.00
\]

Let's calculate this.The velocity of the ball at the end of 6.00 seconds is approximately \( -1.05 \, \text{m/s} \). The negative sign indicates that the ball is moving in the opposite direction (downhill).

Would you like more details or have any questions?

Here are some related questions you might explore:

1. How long will it take for the ball to come to a complete stop?
2. What distance does the ball travel during the 6.00 seconds?
3. What would be the velocity if the acceleration were doubled?
4. What is the total change in velocity after 6.00 seconds?
5. How would a positive acceleration affect the ball's motion?

**Tip:** A negative final velocity means the ball has reversed its direction.

Learn how to calculate the final velocity of an object after 6.00 seconds using the equation of motion. Includes step-by-step solution with initial velocity and acceleration data. Suitable for high school physics students.

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