in the rugby championship, 4 teams each play each other twice. how many games are played in total?

In this rugby championship, each of the 4 teams plays every other team twice (home and away). To calculate the total number of games played, we can follow these steps:

1. The number of teams is 4.
2. Each team plays every other team twice. The number of ways to choose 2 teams from 4 is calculated using combinations:  
\[
\binom{4}{2} = \frac{4 \times 3}{2} = 6
\]
3. Since each matchup happens twice (home and away), we multiply this by 2:
\[
6 \times 2 = 12
\]

Therefore, a total of **12 games** are played.

Would you like further details or have any questions?

Here are 5 related questions:
1. How would the total games change if each team played every other team only once?
2. What if there were 5 teams playing in the tournament, still playing each other twice?
3. How many games would there be if 6 teams played each other twice?
4. How do we calculate the total games if teams are divided into two groups?
5. What if each team played the others three times?

**Tip:** When calculating games between teams, combinations \(\binom{n}{2}\) help find matchups, then adjust for repetitions like home and away.

In the rugby championship, 4 teams each play each other twice. How many games are played in total?

Learn how to calculate the total number of games played in a 4-team rugby championship where each team plays the other twice (home and away). This problem covers key combinatorics concepts and uses the combination formula to count matchups. Suitable for Grades 6-8.

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