Math Problem Statement

기온이 x°C일 때, 공기 중에서 소리의 속력은 약 초속 (0.6x + 331)m이다. 기온이 10°C일 때, 5초 동안 소리가 전달되는 거리를 구하시오.

Solution

The problem states that the speed of sound in air at a temperature of xCx^\circ C is approximately (0.6x+331)m/s(0.6x + 331)\,\text{m/s}. You are tasked with calculating the distance a sound travels in 5 seconds when the temperature is 10C10^\circ C.


Step-by-Step Solution:

  1. Determine the speed of sound at 10C10^\circ C: Using the given formula: v=0.6x+331v = 0.6x + 331 Substitute x=10x = 10: v=0.6(10)+331=6+331=337m/s.v = 0.6(10) + 331 = 6 + 331 = 337\,\text{m/s}.

  2. Calculate the distance traveled in 5 seconds: Distance is given by: Distance=Speed×Time.\text{Distance} = \text{Speed} \times \text{Time}. Substituting the speed v=337m/sv = 337\,\text{m/s} and time t=5st = 5\,\text{s}: Distance=337×5=1685m.\text{Distance} = 337 \times 5 = 1685\,\text{m}.


Final Answer:

The sound travels a distance of 1685 meters in 5 seconds when the temperature is 10C10^\circ C.


Would you like a detailed explanation of any step? Here are some related questions:

  1. How does the speed of sound change with temperature?
  2. What is the speed of sound at 0C0^\circ C?
  3. How long would it take for sound to travel 1 kilometer at 10C10^\circ C?
  4. Can this formula be applied in environments other than air (e.g., water)?
  5. What happens to the speed of sound as the temperature decreases?

Tip: Always remember that the speed of sound depends on temperature due to air's changing density and elasticity!

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Math Problem Analysis

Mathematical Concepts

Linear Equations
Distance and Speed Relationship

Formulas

v = 0.6x + 331
Distance = Speed × Time

Theorems

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Suitable Grade Level

Grades 7-9