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The problem states that a student needs 25.0 g of butanoic acid and has 350. g of a 36.1% w/w solution of butanoic acid in water. We are asked to calculate the mass of the solution that contains the required 25.0 g of butanoic acid.

### Step-by-Step Solution:

1. **Understanding the 36.1% w/w solution**:
   - A 36.1% w/w (weight/weight) solution means that in every 100 g of the solution, 36.1 g is butanoic acid.

2. **Let the mass of the solution required be \( x \) grams**.  
   From the percentage concentration:
   \[
   \text{mass of butanoic acid} = \frac{36.1}{100} \times x = 0.361x
   \]
   
3. **We need 25.0 g of butanoic acid**, so set the equation:
   \[
   0.361x = 25.0
   \]
   
4. **Solve for \( x \)**:
   \[
   x = \frac{25.0}{0.361} \approx 69.25 \text{ grams}
   \]

5. **Check if there's enough solution**:
   - The student has 350. g of the solution available, which is more than the 69.25 g required, so there **is enough solution**.

### Final Answer:
The student should use **69.3 g** of the solution (rounded to three significant digits).

Would you like more details or have any questions?

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Here are 5 related questions to deepen your understanding:
1. What mass of the solution would be needed if the butanoic acid required was doubled?
2. How would you calculate the mass if the solution concentration was 50% instead of 36.1%?
3. If only 50 g of the solution was available, what would be the maximum amount of butanoic acid the student could get?
4. How does the concept of w/w concentration differ from other concentration units like molarity?
5. What would happen to the required mass of the solution if the concentration was reduced by half?

### Tip:
When dealing with percentage concentration problems, always express the percentage as a decimal (e.g., 36.1% becomes 0.361) to simplify your calculations.

A chemistry student needs 25.0 g of butanoic acid for an experiment. She has available 350. g of a 36.1% w/w solution of butanoic acid in water. Calculate the mass of solution the student should use.

Learn how to calculate the mass of a 36.1% w/w butanoic acid solution needed to obtain 25.0 g of butanoic acid. This solution includes algebraic manipulations, percentage concentration concepts, and step-by-step calculations.

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