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The problem you're working on asks you to determine the mass of solution a chemistry student should use, given that they need 20.00 g of 1-bromobutane from a 42.6% w/w solution in diethyl ether. The total mass of available solution is 0.20 kg.

Here's how to approach the problem:

1. **Understand the percentage by mass (w/w)**:
   - The 42.6% w/w means that for every 100 grams of the solution, 42.6 grams is 1-bromobutane.

2. **Set up the equation**:
   Let \( m_{\text{solution}} \) be the mass of the solution the student should use. The mass of 1-bromobutane in this solution is:
   \[
   0.426 \times m_{\text{solution}} = 20.00 \, \text{g}
   \]
   Solving for \( m_{\text{solution}} \):
   \[
   m_{\text{solution}} = \frac{20.00 \, \text{g}}{0.426} \approx 46.95 \, \text{g}
   \]

3. **Check if there's enough solution**:
   The student has 0.20 kg (200.00 g) of the solution, and the calculated mass is 46.95 g, which is less than 200.00 g. Therefore, it is possible for the student to use 46.95 g of the solution.

The mass of the solution required is **46.95 g**.

Would you like further clarification or have any questions? Here are five related questions to expand on this topic:

1. How would you calculate the mass of 1-bromobutane if the percentage composition was different?
2. What is the role of diethyl ether in this solution?
3. If the solution was more concentrated, would the required mass of the solution increase or decrease?
4. How would you calculate the molarity of the solution if the molar mass of 1-bromobutane was given?
5. What is the difference between w/w and w/v concentration units?

**Tip:** When working with percentage concentrations, always confirm whether the problem refers to mass/mass, mass/volume, or volume/volume percentages, as each has a different approach.

A chemistry student needs 20.00 g of 1-bromobutane for an experiment. He has available 0.20 kg of a 42.6% w/w solution of 1-bromobutane in diethyl ether. Calculate the mass of solution the student should use.

Learn how to calculate the mass of a solution required to obtain 20.00 g of 1-bromobutane using a 42.6% w/w solution. This problem involves the concepts of percentage concentration and algebraic equations, suitable for high school chemistry students.

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