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The problem asks for the mass of solution that contains 65.0 g of acetyl bromide, given that the available solution is 450.0 g of a 23.8% w/w (weight/weight) solution of acetyl bromide in chloroform.

Here’s how we solve it:

1. **Set up the percentage concentration equation**:
   - A 23.8% w/w solution means that 23.8 g of acetyl bromide are present in every 100 g of solution.

   Therefore, in general: 
   \[
   \text{Mass of acetyl bromide} = \text{Percentage} \times \text{Mass of solution}
   \]
   Where the percentage is expressed as a decimal (23.8% = 0.238).

2. **Rearrange the formula to solve for the mass of the solution**:
   \[
   \text{Mass of solution} = \frac{\text{Mass of acetyl bromide needed}}{\text{Percentage concentration (as decimal)}}
   \]
   Plugging in the values:
   \[
   \text{Mass of solution} = \frac{65.0 \, \text{g}}{0.238}
   \]
   \[
   \text{Mass of solution} = 273.11 \, \text{g}
   \]

3. **Compare with available solution**:
   The student has 450.0 g of solution available. Since 273.11 g is less than 450.0 g, there is enough solution.

### Final Answer:
The mass of the solution the student should use is **273 g** (rounded to three significant figures).

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Do you want more details or have any other questions?

Here are 5 questions to expand this topic:

1. How would the solution calculation change if the concentration were 30% instead of 23.8%?
2. What if the student only had 200 g of the 23.8% solution? What would happen?
3. How do you calculate weight/volume percentage instead of weight/weight?
4. Can you explain how the concept of molarity differs from percentage solutions?
5. How would you calculate the volume if the solution density was provided?

**Tip:** Always check units and significant figures, especially in chemistry-related calculations!

A chemistry student needs 65.0 g of acetyl bromide for an experiment. He has available 450.0 g of a 23.8% w/w solution of acetyl bromide in chloroform. Calculate the mass of solution the student should use.

This chemistry problem involves calculating the mass of solution required to obtain 65.0 g of acetyl bromide from a 23.8% w/w solution in chloroform. The step-by-step solution involves applying percentage concentration and unit conversion.

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