Math Problem Statement

As part of a race, you foolishly try to take a shortcut across a railway bridge over a river full of hungry crocodiles. You make it 3/8 of the way across the bridge when you notice a train traveling 40 km/h approaching the bridge from behind you. If you run as fast as you can back towards the train you will make it to the end of the bridge just as the train arrives there. If you run as fast as you can in the other direction, you will make it to the other end of the bridge just as the train arrives there. In both cases a very fast leap will get you out of the way of the train. How fast can you run ? The solution to this problem must NOT introduce any variables or equations.

Solution

To determine your running speed without introducing variables or equations, let's think conceptually and logically through the problem:

  1. Bridge Setup: You are 3/83/8 of the way across the bridge when the train starts approaching. This leaves 3/83/8 of the bridge's length between you and the starting point of the bridge and 5/85/8 of the bridge's length to the far end.

  2. Relative Movement: If you choose to run back toward the train, you cover 3/83/8 of the bridge's length while the train covers the entire length of the bridge. Alternatively, if you run toward the far end, you cover 5/85/8 of the bridge's length while the train covers the entire length of the bridge.

  3. Key Insight: The train takes the same amount of time to cross the bridge in either scenario. Your running speed must therefore have a consistent proportional relationship to the train's speed because your time to reach either end matches the train's time to cross the bridge.

  4. Proportions:

    • When running back, you are moving against the train's motion relative to the bridge. The train "sees" you as taking 138=581 - \frac{3}{8} = \frac{5}{8} of the bridge's length to itself.
    • When running forward, you "gain" an extra 28\frac{2}{8}, making running scenarios add out.

Running speed logically realizes symmetry

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Math Problem Analysis

Mathematical Concepts

Proportional Reasoning
Relative Motion
Speed-Time-Distance Relationships

Formulas

Speed = Distance / Time
Relative Speed in Opposite Directions = Train Speed + Runner Speed
Relative Speed in Same Direction = Train Speed - Runner Speed

Theorems

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Suitable Grade Level

Grades 9-11