Train + leaves station x for station Y at 3 porn train & bavdling at three quatuor of the speed of I leaus Y the two tran pare each other y for xaram at a Station 2, whine the distance between x and 2 is the fifth of that blew X and Y How many How many m dos town & take for its foury.

It seems like your message got a bit mixed up, but based on what I understand, you're asking about two trains traveling between two stations, X and Y, at different speeds and times, and you're trying to figure out how long it takes one of the trains to cover a certain distance. I'll need to clarify the problem a bit more:

1. You mention two stations (X and Y), with a train leaving Station X for Station Y. The other train is traveling from Station Y to Station X.
2. The two trains meet at some intermediate station (let's call it Station 2).
3. The distance between Station X and Station 2 is a fraction (one-fifth) of the distance between X and Y.
4. There's also something about one train traveling at a speed that's a fraction (three-quarters) of the other.

Let’s break it down with this interpretation:
- Train A leaves station X, and Train B leaves station Y.
- Train A travels at three-quarters of the speed of Train B.
- They meet at Station 2, and the distance from X to Station 2 is one-fifth of the total distance from X to Y.

To solve this, we would typically use the formula for speed, distance, and time:

\[
\text{Distance} = \text{Speed} \times \text{Time}
\]

Could you confirm these details, or clarify anything else?

Solve a train problem where two trains leave from stations X and Y at different speeds and meet at an intermediate station. Learn to apply the speed, distance, and time formula and handle ratios of speeds between two objects in motion. Suitable for Grades 9-12.

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