Math Problem Statement

The area of triangle ABC is 1/2 cm^2. (a) Calculate the value of x.

Solution

The problem you've uploaded shows a right triangle ABCABC with the right angle at CC. The triangle has the following dimensions:

  • AB=17AB = 17 cm (the hypotenuse)
  • BC=8BC = 8 cm (one of the legs)
  • AC=xAC = x cm (the other leg, which is unknown)

We are asked to calculate the value of xx.

Solution:

To solve for xx, we can use the Pythagorean Theorem, which states: AB2=AC2+BC2AB^2 = AC^2 + BC^2 Substituting the known values: 172=x2+8217^2 = x^2 + 8^2

This simplifies to: 289=x2+64289 = x^2 + 64

Next, isolate x2x^2 by subtracting 64 from both sides: x2=28964x^2 = 289 - 64 x2=225x^2 = 225

Finally, solve for xx by taking the square root of both sides: x=225=15cmx = \sqrt{225} = 15 \, \text{cm}

Answer:

The value of xx is 15 cm.

Would you like further details or have any questions?

Relative Questions:

  1. What is the Pythagorean Theorem, and when is it applicable?
  2. How would the approach change if the hypotenuse were unknown instead?
  3. Can the triangle inequality theorem verify the existence of a triangle with given sides?
  4. How do you find the area of this triangle?
  5. What would happen if BCBC was longer than the hypotenuse?

Tip:

When working with right triangles, always consider using the Pythagorean Theorem to solve for missing sides, but ensure you correctly identify which side is the hypotenuse.

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Math Problem Analysis

Mathematical Concepts

Geometry
Pythagorean Theorem
Right Triangle

Formulas

Pythagorean Theorem: a^2 + b^2 = c^2
Area of a triangle: (1/2) * base * height

Theorems

Pythagorean Theorem

Suitable Grade Level

Grades 8-10