Math Problem Statement

In the triangle, AB = 18, AC = 17, and BC = x. Solve for x using the Pythagorean theorem.

Solution

The triangle you provided has sides labeled as follows:

  • AB=18AB = 18
  • AC=17AC = 17
  • BC=xBC = x (the unknown)

It appears to be a right triangle with the right angle at vertex CC, since the problem seems to involve the use of the Pythagorean theorem. If that is correct, we can apply the Pythagorean theorem, which states:

AB2=AC2+BC2AB^2 = AC^2 + BC^2

Substituting the known values:

182=172+x218^2 = 17^2 + x^2

This simplifies to:

324=289+x2324 = 289 + x^2

Now, solve for x2x^2:

x2=324289=35x^2 = 324 - 289 = 35

Finally, take the square root of both sides:

x=355.92x = \sqrt{35} \approx 5.92

Thus, BC5.92BC \approx 5.92.

Would you like more details or have any questions about this?

Here are 5 related questions to explore further:

  1. What would happen if we changed one of the side lengths in this triangle?
  2. How would you solve this problem if you didn't know it was a right triangle?
  3. What is the relationship between angles in a right triangle like this one?
  4. How can you apply the Pythagorean theorem in three dimensions?
  5. How do different triangle properties change if you change the type of triangle (right vs. obtuse)?

Tip: Whenever dealing with right triangles, identifying the hypotenuse (the side opposite the right angle) helps you set up the Pythagorean theorem correctly!

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Math Problem Analysis

Mathematical Concepts

Geometry
Pythagorean Theorem
Algebra

Formulas

Pythagorean theorem: AB^2 = AC^2 + BC^2

Theorems

Pythagorean Theorem

Suitable Grade Level

Grades 8-10